1403. Minimum Subsequence in Non-Increasing Order 链接到标题 对数组进行排序，然后依次取出当前最大值，比较当前取出数值和与剩余数值和，如果大于，则返回取出数字。class Solution: def minSubsequence(self, nums: List[int]) -> List[int]: N = len(nums) total = sum(nums) nums.sort() ret = [] t = 0 while True: x = nums.pop() t += x ret.append(x) if t * 2 > total……